\(=\dfrac{1}{\sqrt{2}}\left(\sqrt{24-6\sqrt{7}}-\sqrt{24+6\sqrt{7}}\right)\)
\(=\dfrac{1}{\sqrt{2}}\left(\sqrt{21}-\sqrt{3}-\sqrt{21}-\sqrt{3}\right)\)
=-2*căn 3/2=-căn 6
\(=\dfrac{1}{\sqrt{2}}\left(\sqrt{24-6\sqrt{7}}-\sqrt{24+6\sqrt{7}}\right)\)
\(=\dfrac{1}{\sqrt{2}}\left(\sqrt{21}-\sqrt{3}-\sqrt{21}-\sqrt{3}\right)\)
=-2*căn 3/2=-căn 6
THỰC HIỆN PHÉP TÍNH
1,\(\sqrt{3+\sqrt{5}}.\sqrt{2}\)
2,\(\sqrt{3-\sqrt{5}.\sqrt{8}}\)
3,\((\sqrt{\dfrac{3}{4}}-\sqrt{3}+5\sqrt{\dfrac{4}{3})}.\sqrt{12}\)
4,\((\sqrt{\dfrac{1}{7}}-\sqrt{\dfrac{16}{7}}+\sqrt{7}):\sqrt{7}\)
5, \(\sqrt{36-12\sqrt{5}}:\sqrt{6}\)
6,\(\sqrt{3-\sqrt{5}:}\sqrt{2}\)
tính \(\sqrt{7-2\sqrt{12}}\) kết quả là
a, \(7-2\sqrt[]{12}\)
b, \(2\sqrt{12}-7\)
c, 2-\(\sqrt{3}\)
d, \(\sqrt{3}-2\)
\(A=\sqrt{12-3\sqrt{7}}-\sqrt{12+3\sqrt{7}}\)
\(B=\sqrt{4+\sqrt{10+2\sqrt{5}}}+\sqrt{4-\sqrt{10+2\sqrt{5}}}\)\(C=\sqrt{3-\sqrt{5}}+\sqrt{3+\sqrt{5}}\)
A = \(\sqrt{12-3\sqrt{7}}-\sqrt{12+3\sqrt{7}}\)
Tính A
* Thực hiện phép tính
a, A= \(\sqrt{12-3\sqrt{7}}-\sqrt{12+3\sqrt{7}}\)
b, B= \(\sqrt{4+\sqrt{10+2\sqrt{5}}}+\sqrt{4-\sqrt{10+2\sqrt{5}}}\)
c, C= \(\sqrt{3-\sqrt{5}}+\sqrt{3+\sqrt{5}}\)
\(\frac{\sqrt{44-15\sqrt{7}}+\sqrt{32-3\sqrt{7}}}{\sqrt{12-3\sqrt{7}}}-\sqrt{21-12\sqrt{3}}\) rút gọn biểu thức
\(\sqrt{3\sqrt{7}-1+2\sqrt{12-3\sqrt{7}}}-\sqrt{2\sqrt{7}+1}\)
Rút gọn các biểu thức sau
a) \(\dfrac{1}{\sqrt{3}}+\dfrac{1}{3\sqrt{2}}+\dfrac{1}{\sqrt{3}}\dfrac{\sqrt{3}-\sqrt{2}}{2\sqrt{3}}\) b) \(\sqrt{12-3\sqrt{7}}-\sqrt{12+3\sqrt{7}}\) c) \(\sqrt[3]{\dfrac{3}{4}}.\sqrt[3]{\dfrac{9}{16}}\)
d) \(\dfrac{\sqrt[3]{54}}{\sqrt[3]{-2}}\) e) \(\sqrt[3]{5\sqrt{2}+7}-\sqrt[3]{5\sqrt{2}-7}\)
Rút gọn biểu thức : \(\sqrt{3\sqrt{7}-1+2\sqrt{12-3\sqrt{7}}}-\sqrt{2\sqrt{7}+1}\)