Question

Rút gọn E

E=\([\dfrac{1}{\sqrt{x}-1}-\dfrac{1}{x\sqrt{x}-1}].\dfrac{3\sqrt{x}-3}{x+\sqrt{x}}\)

Answer 1

\(E=\left(\dfrac{1}{\sqrt{x}-1}-\dfrac{1}{x\sqrt{x}-1}\right)\cdot\dfrac{3\sqrt{x}-3}{x+\sqrt{x}}\)

\(=\dfrac{x+\sqrt{x}}{\sqrt{x}\left(\sqrt{x}-1\right)}\cdot\dfrac{3\left(\sqrt{x}-1\right)}{x+\sqrt{x}}\)

\(=\dfrac{3}{\sqrt{x}}\)