`a)(x+2)^2+2(x^2-4)+(x-2)^2`
`=(x+2)^2+2(x-2)(x+2)+(x-2)^2`
`=(x+2+x-2)^2=(2x)^2=4x^2`
`b)x^2-x+1/4`
`=x^2-2.x .1/2+1/4=(x-1/2)^2`
`c)(x+y)^3-(x-y)^3`
`=(x+y-x+y)[(x+y)^2+(x+y)(x-y)+(x-y)^2]`
`=2y(x^2+2xy+y^2+x^2-y^2+x^2-2xy+y^2)`
`=2y(3x^2+y^2)`
a) \(\left(x+2\right)^2+2\left(x^2-4\right)+\left(x-2\right)^2\)
\(=\left(x+2\right)^2+2\left(x+2\right)\left(x-2\right)+\left(x-2\right)^2\)
\(=\left(x+2+x-2\right)^2=\left(2x\right)^2=4x^2\)
b) \(x^2-x+\dfrac{1}{4}=\left(x-\dfrac{1}{2}\right)^2\)
c) \(\left(x+y\right)^3-\left(x-y\right)^3=\left(x^3+3x^2y+3xy^2+y^3\right)-\left(x^3-3x^2y+3xy^2-y^3\right)=6x^2y+2y^3=2y\left(3x^2+y^2\right)\)
a)(x+2)2+2(x2−4)+(x−2)2a)(x+2)2+2(x2-4)+(x-2)2
=(x+2)2+2(x−2)(x+2)+(x−2)2
=(x+2)2+2(x-2)(x+2)+(x-2)2
=(x+2+x−2)2=(2x)2=4x2
=(x+2+x-2)2=(2x)2=4x2
b)x2−x+14b)x2-x+14
=x2−2.x.12+14
=(x−12)2=x2-2.x.12+14
=(x-12)2
c)(x+y)3−(x−y)3c)(x+y)3-(x-y)3
=(x+y−x+y)[(x+y)2+(x+y)(x−y)+(x−y)2]
=(x+y-x+y)[(x+y)2+(x+y)(x-y)+(x-y)2]
=2y(x2+2xy+y2+x2−y2+x2−2xy+y2)
=2y(x2+2xy+y2+x2-y2+x2-2xy+y2)
=2y(3x2+y2)
c) 2x2(x +1) + 4x(x +1); d) 2 x(y - 1) - 2
