Question

phân tích đa thức thành nhân tử :(x + 1)^2 - 4(x + 1)y^2 + 4y^4
giúp mình với ạ

Answer 1

\(\left(x+1\right)^2-4\left(x+1\right)y^2+4y^4\\ =\left(x+1\right)^2-2\cdot\left(x+1\right)^2\cdot2y^2+\left(2y^2\right)^2\\ =\left[\left(x+1\right)-2y^2\right]^2\\ =\left(x-2y^2+1\right)^2\)

Answer 2

\(\left(x+1\right)^2-4\left(x+1\right)y^2+4y^4\)
\(=\left(x+1\right)^2-2\left(x+1\right)2y^2+\left(2y\right)^2\)
\(=\left(x+1-2y^2\right)^2\)