\(V_{C_2H_5OH}=\dfrac{90.500}{100}=450\left(ml\right)\)
=> \(V_{dd.cồn.75^o}=\dfrac{450.100}{75}=600\left(ml\right)\)
\(V_{C_2H_5OH}=\dfrac{500.90}{100}=450\left(ml\right)\\ \rightarrow V_{ddC_2H_5OH\left(75^o\right)}=\dfrac{450}{75}.100=600\left(ml\right)\)