Nửa chu vi tam giác ABC là:
\(P=\dfrac{a+b+c}{2}=\dfrac{12+16+20}{2}=\dfrac{2\left(6+8+10\right)}{2}=24\)(đvđd)Diện tích tam giác ABC là:
\(S=\sqrt{P\cdot\left(P-a\right)\left(P-b\right)\left(P-c\right)}\)
\(=\sqrt{24\cdot\left(24-12\right)\left(24-16\right)\left(24-20\right)}\)
\(=\sqrt{24\cdot12\cdot8\cdot4}\)
\(=2\sqrt{6}\cdot2\sqrt{3}\cdot2\sqrt{2}\cdot2\)
\(=16\sqrt{36}=96\)(đvdt)