a: \(A=\dfrac{x-\sqrt{x}+1}{\sqrt{x}-1}-\dfrac{1}{\sqrt{x}-1}=\dfrac{x-\sqrt{x}}{\sqrt{x}-1}=\sqrt{x}\)
b: \(P=\dfrac{\sqrt{a}+3+\sqrt{a}-3}{a-9}\cdot\dfrac{\sqrt{a}-3}{\sqrt{a}}\)
\(=\dfrac{2\sqrt{a}}{\sqrt{a}}\cdot\dfrac{1}{\sqrt{a}+3}=\dfrac{2}{\sqrt{a}+3}\)
Đúng 0
Bình luận (0)