a: \(\Leftrightarrow\sqrt{3x+1}=1-3x\)
\(\Leftrightarrow\left\{{}\begin{matrix}x< =\dfrac{1}{3}\\\left(3x+1+1-3x\right)\left(3x+1-1+3x\right)=0\end{matrix}\right.\)
=>x=0
b: \(\Leftrightarrow\dfrac{5x+7}{x+3}=49\)
=>49x+147=5x+7
=>44x=-140
hay x=-35/11
Với giá trị nào của x thì mỗi căn thức sau đây có nghĩa:
a) \(\sqrt{\dfrac{x}{3}}\)
b) \(\sqrt{-5x}\)
c) \(\sqrt{4-x}\)
d) \(\sqrt{3x+7}\)
e) \(\sqrt{-3x+4}\)
f) \(\sqrt{\dfrac{1}{-1+x}}\)
g) \(\sqrt{1+x^2}\)
h) \(\sqrt{\dfrac{5}{x-2}}\)
Tìm x
1) \(\sqrt{\dfrac{3x-1}{x+2}}=2\)
2)\(\sqrt{\dfrac{5x-7}{2x- 1}}=2\)
3)\(\dfrac{\sqrt{x}-2}{\sqrt{x}+1}=\dfrac{\sqrt{x}-1}{\sqrt{x}+3}\)
4) \(\dfrac{\sqrt{x}-3}{\sqrt{x}+2}=\dfrac{\sqrt{x}-2}{\sqrt{x}+1}\)
Giai phương trình
a) \(1+\sqrt{3x+1}=3x\)
b) \(\sqrt{2+\sqrt{3x-5}}=\sqrt{x+1}\)
c) \(\sqrt{\frac{5x+7}{x+3}}=4\)
d) \(\frac{\sqrt{5x+7}}{\sqrt{x+3}}=4\)
a) \(\sqrt{3x^2-5x+7}\)+\(\sqrt{3x^2+x+1}\) = 12x-12
b) \(\sqrt{x^2+33}\)+3 = 2x+\(\sqrt{x^2-12}\)
c) 3x-\(8\sqrt{x+14}\) = \(2\sqrt{2x-3}\) - 28
d) \(x^2\)+\(\sqrt{x+7}\) = 7
tìm ĐKXĐ
1, \(\sqrt{6x+1}\)
2,\(\dfrac{\sqrt{3}-4}{\sqrt{3x-5}}\)
3, \(\sqrt{\dfrac{2\sqrt{15}-\sqrt{59}}{x-7}}\)
4,\(\sqrt{\dfrac{-3x}{1-\sqrt{2}}}\)
5, \(\sqrt{\sqrt{5}-\sqrt{3}x}\)
1\(\sqrt{5+2\sqrt{8}}-\sqrt{5-2\sqrt{8}}\) 2)\(\dfrac{\sqrt{x^2+2\sqrt{3x}+3}}{x^2-3}\) 3) \(\dfrac{\sqrt{x^2-5x+6}}{\sqrt{x-2}}\) 4)\(\dfrac{\sqrt{\left(x-4\right)^2}}{x^2-5x+4}\) 5) \(\dfrac{3x+1}{\sqrt{9x^2+6x+1}}\)
1. \(1+\sqrt{3x-1}=3x\)
2. \(\sqrt{2+\sqrt{3x-5}=\sqrt{x+1}}\)
3.\(\sqrt{\frac{5x+7}{x+3}}=4\)
4. \(\frac{\sqrt{5x+7}}{\sqrt{x+3}}=4\)
5.\(\sqrt{5x^2}=2x+1\)
b)\(\sqrt{4x-20}+\sqrt{x+5}-\dfrac{1}{3}\sqrt{9x-45}=4\)
c) \(\sqrt{\dfrac{3x-2}{x+1}}=3\)
d) \(\dfrac{\sqrt{5x-4}}{\sqrt{x+2}}=2\)
Bài 1:Tìn ĐKXĐ
a.\(\sqrt{\dfrac{2}{^{^{^{ }}}x^2}}\)
b.\(\sqrt{\dfrac{-3}{3x+5}}\)
Bài 2:
a.\(\dfrac{2+\sqrt{2}}{1+\sqrt{2}}\)
b.\(\left(\sqrt{28}-2\sqrt{14}+\sqrt{7}\right)\sqrt{7}+7\sqrt{8}\)
c,\(\left(\sqrt{14}-3\sqrt{2}\right)^2+6\sqrt{28}\)
Trả lời giúp mình với ạ!Mình cảm ơn nhiều!
1) ( \(3\sqrt{50}-5\sqrt{18}+3\sqrt{8}\) ).\(\sqrt{2}\)
2. Tìm điều kiện:
1)\(\sqrt{-10x}\) 6) \(\sqrt{\dfrac{3x+21}{-5}}\)
2) \(\sqrt{6-3x}\) 7) \(\sqrt{\left(x^2+1\right).2x}\)
3) \(\dfrac{-4}{\sqrt{4x+6}}\) 8) \(\sqrt{\left(-x^2-2\right)}.3x\)
4) \(\dfrac{5}{\sqrt{2x}}\) 9) \(\sqrt{\dfrac{1}{\left(x-1\right)^2}}\)
5) \(\sqrt{\dfrac{-1}{2x-6}}\)
hộ mk với tí nx pk nộp r ;-; help
