\(\left(x-3\right)^2=5\\ \Leftrightarrow\left[{}\begin{matrix}x-3=\sqrt{5}\\x-3=-\sqrt{5}\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=3+\sqrt{5}\\x=3-\sqrt{5}\end{matrix}\right.\)
\(\left(x-3\right)^2=5\)
⇒ \(\left[{}\begin{matrix}x-3=\sqrt{5}\\x-3=-\sqrt{5}\end{matrix}\right.\)
⇒ \(\left[{}\begin{matrix}x=\sqrt{5}+3\\x=3-\sqrt{5}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x-3=\sqrt{5}\\x-3=-\sqrt{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\sqrt{5}+3\\x=-\sqrt{5}+3\end{matrix}\right.\)
( x − 3 )2= 5
=>2x-6=5
2x=5+6=11
x=11:2
x=Tự tính
Hoặc
(x−3)2=5(x−3)2=5
⇒ [x−3=√5x−3=−√5[x−3=5x−3=−5
⇒ [x=√5+3x=3−√5
