Question

Giải phương trình: tìm đkxđ 

\(5-\dfrac{96}{x^2-16}=\dfrac{2x-1}{x+4}-\dfrac{3x-1}{4-x}\)

Answer 1

\(đk:\left\{{}\begin{matrix}x\ne4\\x\ne-4\end{matrix}\right.\\ 5-\dfrac{96}{x^2-16}=\dfrac{2x-1}{x+4}+\dfrac{3x-1}{x-4}\\ \Rightarrow5.\left(x^2-16\right)-96=\left(2x-1\right)\left(x-4\right)+\left(3x-1\right)\left(x+4\right)\\ \Rightarrow5x^2-80-96=2x^2-x-8x+4+3x^2-x+12x-4\\ \Rightarrow-176=2x\\ \Rightarrow x=-88\left(t/mđk\right)\)

Answer 2

=>5x^2-80-96=(2x-1)(x-4)+(3x-1)(x+4)

=>5x^2-176=2x^2-9x+4+3x^2+12x-x-4

=>5x^2-176=5x^2+2x

=>2x=-176

=>x=-88

Answer 3