Question

Giải phương trình sau

(2x - 6)(4x + 16) = 0

 

Answer 1

`(2x-6)(4x+16)=0`

`@TH1:`

`2x-6=0`

`<=>2x=6`

`<=>x=3`

`@TH2:`

`4x+16=0`

`<=>4x=-16`

`<=>x=-4`

Answer 2

\(\left(2x-6\right).\left(4x+16\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-6=0\\4x+16=0\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}2x=6\\4x=-16\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-4\end{matrix}\right.\)

\(S=\left\{3;-4\right\}\)

Answer 3

\(\left(2x-6\right)\left(4x+16\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2x-6=0\\4x+16=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=6\\4x=-16\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=3\\x=-4\end{matrix}\right.\)

Answer 4

(2x-6)(4X+16)=0

<=>\(\left[{}\begin{matrix}2x-6=0\\4x+16=0\end{matrix}\right.\)

<=>\(\left[{}\begin{matrix}x=3\\x=-4\end{matrix}\right.\)

vậy tập nghiệm S=\(\left\{3;-4\right\}\)