Thế :
\(x^2\left(x^2+2\right)=y^3\)
\(x^4+2x^3-y^3=0\)
\(\Rightarrow y=\left(-1\right)^{\frac{2}{3}}x^{\frac{2}{3}}\sqrt[3]{x^2+2}\)
Lưu ý : \(x^{\frac{2}{3}}=\sqrt[3]{x^2}\)
Giải
\(y=x^{\frac{2}{3}}\sqrt[3]{x^2+2}\)
\(y=-\sqrt[3]{-1}x^{\frac{2}{3}}\sqrt[3]{x^2+2}\)
\(\Leftrightarrow y=\left(-1\right)^{\frac{2}{3}}x^{\frac{2}{3}}\sqrt[3]{x^2+2}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\y=0\end{cases}}\)