Các câu hỏi tương tự
27 tháng 11 2023 lúc 21:00
Giải hpt:a)left{{}begin{matrix}dfrac{2y-5x}{3}+5dfrac{y+27}{4}-2xdfrac{x+1}{3}+ydfrac{6y-5x}{7}end{matrix}right.b)left{{}begin{matrix}dfrac{1}{2}left(x+2right)left(y+3right)-dfrac{1}{2}xy50dfrac{1}{2}xy-dfrac{1}{2}left(x-2right)left(y-2right)32end{matrix}right.c)left{{}begin{matrix}left(x+20right)left(y-1right)xyleft(x-10right)left(y+1right)xyend{matrix}right.d)left{{}begin{matrix}dfrac{2}{x+2y}+dfrac{1}{y+2x}3dfrac{4}{x+2y}-dfrac{3}{y+2x}1end{matrix}right.e)left{{}begin{matrix}dfrac{3x}{x+1}-df...
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Giải hpt:
a)\(\left\{{}\begin{matrix}\dfrac{2y-5x}{3}+5=\dfrac{y+27}{4}-2x\\\dfrac{x+1}{3}+y=\dfrac{6y-5x}{7}\end{matrix}\right.\)
b)\(\left\{{}\begin{matrix}\dfrac{1}{2}\left(x+2\right)\left(y+3\right)-\dfrac{1}{2}xy=50\\\dfrac{1}{2}xy-\dfrac{1}{2}\left(x-2\right)\left(y-2\right)=32\end{matrix}\right.\)
c)\(\left\{{}\begin{matrix}\left(x+20\right)\left(y-1\right)=xy\\\left(x-10\right)\left(y+1\right)=xy\end{matrix}\right.\)
d)\(\left\{{}\begin{matrix}\dfrac{2}{x+2y}+\dfrac{1}{y+2x}=3\\\dfrac{4}{x+2y}-\dfrac{3}{y+2x}=1\end{matrix}\right.\)
e)\(\left\{{}\begin{matrix}\dfrac{3x}{x+1}-\dfrac{2}{y+4}=4\\\dfrac{2x}{x+1}-\dfrac{5}{y+4}=9\end{matrix}\right.\)
26 tháng 11 2023 lúc 15:22
Giải hpta)left{{}begin{matrix}dfrac{4}{2x-3y}+dfrac{5}{3x+y}-2dfrac{3}{3x+y}-dfrac{5}{2x-3y}21end{matrix}right.b)left{{}begin{matrix}dfrac{7}{x-y+2}-dfrac{5}{x+y-1}dfrac{9}{2}dfrac{3}{x-y+2}+dfrac{2}{x+y-1}4end{matrix}right.c)left{{}begin{matrix}dfrac{3}{2x-y}-dfrac{6}{x+y}-1dfrac{1}{2x-y}-dfrac{1}{x+y}0end{matrix}right.d)left{{}begin{matrix}dfrac{4}{x+y-1}-dfrac{5}{2x-y+3}dfrac{5}{2}dfrac{3}{x+y-1}+dfrac{1}{2x-y+3}dfrac{7}{5}end{matrix}right.e)left{{}begin{matrix}dfrac{6}{x-2y}+dfrac{2}{x+2y}3d...
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Giải hpt
a)\(\left\{{}\begin{matrix}\dfrac{4}{2x-3y}+\dfrac{5}{3x+y}=-2\\\dfrac{3}{3x+y}-\dfrac{5}{2x-3y}=21\end{matrix}\right.\)
b)\(\left\{{}\begin{matrix}\dfrac{7}{x-y+2}-\dfrac{5}{x+y-1}=\dfrac{9}{2}\\\dfrac{3}{x-y+2}+\dfrac{2}{x+y-1}=4\end{matrix}\right.\)
c)\(\left\{{}\begin{matrix}\dfrac{3}{2x-y}-\dfrac{6}{x+y}=-1\\\dfrac{1}{2x-y}-\dfrac{1}{x+y}=0\end{matrix}\right.\)
d)\(\left\{{}\begin{matrix}\dfrac{4}{x+y-1}-\dfrac{5}{2x-y+3}=\dfrac{5}{2}\\\dfrac{3}{x+y-1}+\dfrac{1}{2x-y+3}=\dfrac{7}{5}\end{matrix}\right.\)
e)\(\left\{{}\begin{matrix}\dfrac{6}{x-2y}+\dfrac{2}{x+2y}=3\\\dfrac{3}{x-2y}+\dfrac{4}{x+2y}=-1\end{matrix}\right.\)
Bài 1: Giải các hệ PTa) left{{}begin{matrix}dfrac{2}{x}+dfrac{3}{y-2}4dfrac{4}{x}-dfrac{1}{y-2}1end{matrix}right. b) left{{}begin{matrix}3sqrt{x}+2sqrt{y}162sqrt{x}-3sqrt{y}-11end{matrix}right. c) left{{}begin{matrix}dfrac{1}{2}left(x+2right)left(y+1right)dfrac{1}{2}xy+5dfrac{1}{3}left(x-3right)left(y-5right)dfrac{1}{3}xy-dfrac{4}{3}end{matrix}right.
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Bài 1: Giải các hệ PT
a) \(\left\{{}\begin{matrix}\dfrac{2}{x}+\dfrac{3}{y-2}=4\\\dfrac{4}{x}-\dfrac{1}{y-2}=1\end{matrix}\right.\) b) \(\left\{{}\begin{matrix}3\sqrt{x}+2\sqrt{y}=16\\2\sqrt{x}-3\sqrt{y}=-11\end{matrix}\right.\) c) \(\left\{{}\begin{matrix}\dfrac{1}{2}\left(x+2\right)\left(y+1\right)=\dfrac{1}{2}xy+5\\\dfrac{1}{3}\left(x-3\right)\left(y-5\right)=\dfrac{1}{3}xy-\dfrac{4}{3}\end{matrix}\right.\)
giải các hpt sau: a)\(\left\{{}\begin{matrix}4\sqrt{5}-y=3\sqrt{2}\\10x+\sqrt{2}y=-1\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}\dfrac{3x}{4}+\dfrac{2y}{5}=2,3\\x-\dfrac{3y}{5}=0,8\end{matrix}\right.\)
c) \(\left\{{}\begin{matrix}\left|x-1\right|-\dfrac{3}{\sqrt{y-2}}=-1\\2\left|1-x\right|+\dfrac{1}{\sqrt{y-2}}=5\end{matrix}\right.\)cíu zới
18 tháng 1 2022 lúc 18:44
Giải hệ phương trình \(\left\{{}\begin{matrix}\dfrac{x-1}{2x+1}-\dfrac{y-2}{y+2}=1\\\dfrac{3x-3}{2x+1}+\dfrac{2y-4}{y+2}=3\end{matrix}\right.\)
26 tháng 10 2021 lúc 17:19
Ghpt:
a) \(\left\{{}\begin{matrix}x^2+2y^2=2x-2xy+1\\3x^2+2xy-y^2=2x-y+5\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}4xy+4x^2+4y^2+\dfrac{3}{\left(x+y\right)^2}=7\\2x+\dfrac{1}{x+y}=3\end{matrix}\right.\)
giải hệ pt
a, \(\left\{{}\begin{matrix}\dfrac{2}{x+y}+\dfrac{1}{x-y}=3\\\dfrac{1}{x+y}-\dfrac{3}{x-y}=1\end{matrix}\right.\)
giải hệ phương trình
1)left{{}begin{matrix}3x+4y112x-y-11end{matrix}right. 2)left{{}begin{matrix}3x+2y02x+y-1end{matrix}right. 3)left{{}begin{matrix}3x+dfrac{5}{2}y92x+dfrac{1}{3}y2end{matrix}right.
4)left{{}begin{matrix}-x+3y162x+y3end{matrix}right. 5)left{{}begin{matrix}dfrac{-3}{x-y}+dfrac{5}{2x+y}-2dfrac{4}{x-y}-dfrac{10}{2x+y}2end{matrix}right. 6)left{{}begin{matrix}dfrac{1}{x}-dfrac{1}{y}1dfrac{3}{x}+dfrac{4}{y}5end{matrix}right.
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giải hệ phương trình
1)\(\left\{{}\begin{matrix}3x+4y=11\\2x-y=-11\end{matrix}\right.\) 2)\(\left\{{}\begin{matrix}3x+2y=0\\2x+y=-1\end{matrix}\right.\) 3)\(\left\{{}\begin{matrix}3x+\dfrac{5}{2}y=9\\2x+\dfrac{1}{3}y=2\end{matrix}\right.\)
4)\(\left\{{}\begin{matrix}-x+3y=16\\2x+y=3\end{matrix}\right.\) 5)\(\left\{{}\begin{matrix}\dfrac{-3}{x-y}+\dfrac{5}{2x+y}=-2\\\dfrac{4}{x-y}-\dfrac{10}{2x+y}=2\end{matrix}\right.\) 6)\(\left\{{}\begin{matrix}\dfrac{1}{x}-\dfrac{1}{y}=1\\\dfrac{3}{x}+\dfrac{4}{y}=5\end{matrix}\right.\)
22 tháng 1 2024 lúc 19:59
Giải hệ phương trình:
a) \(\left\{{}\begin{matrix}\dfrac{x}{35}-y=2\\y-\dfrac{x}{50}=1\end{matrix}\right.\)
b) \(\left\{{}\begin{matrix}\dfrac{1}{x}+\dfrac{1}{y}=\dfrac{1}{16}\\\dfrac{3}{x}+\dfrac{6}{y}=\dfrac{1}{4}\end{matrix}\right.\)