\(2+\dfrac{3\left(x+1\right)}{3}\le3-\dfrac{x-1}{4}\)
\(\Leftrightarrow2+x+1\le\dfrac{12}{4}-\dfrac{x-1}{4}\)
\(\Leftrightarrow x+3\le\dfrac{13-x}{4}\)
\(\Leftrightarrow\dfrac{4x+12}{4}\le\dfrac{13-x}{4}\)
\(\Leftrightarrow4x+12\le13-x\)
\(\Leftrightarrow4x+x\le13-12\)
\(\Leftrightarrow5x\le1\)
\(\Leftrightarrow x\le\dfrac{1}{5}\)
Vậy: \(x\le\dfrac{1}{5}\)
\(2+\dfrac{3\left(x+1\right)}{3}\le3-\dfrac{x-1}{4}\)
\(\Leftrightarrow\dfrac{12x+36}{12}\le\dfrac{33-3x}{12}\)
\(\Leftrightarrow12x+36\le33-3x\)
\(\Leftrightarrow12x+3x\le-36+33\)
\(\Leftrightarrow15x\le-3\)
\(\Leftrightarrow x\le\dfrac{-1}{5}\)
\(2+\dfrac{3\left(x+1\right)}{3}\le3-\dfrac{x-1}{4}\\ \Leftrightarrow\dfrac{2\cdot12}{12}+\dfrac{12\left(x+1\right)}{12}\le\dfrac{3\cdot12}{12}-\dfrac{3\left(x-1\right)}{12}\)
`<=> 24 + 12x +12 <= 36 - 3x +3`
`<=> 36 + 12x <= 39 -3x`
`<=> 12x +3x <= 39 - 36`
`<=> 15x <= 3`
`<=> x <= 3/15=1/5`
