Question

\(\dfrac{x-2\sqrt{x}-1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)

rút gọn

Answer 1

Hình như sai đề :_:

*Sửa lại:

`(x-2sqrtx+1)/((sqrtx-1)(sqrtx+1))`

`=(sqrtx-1)^2/((sqrtx-1)(sqrtx+1))`

`=(sqrtx-1)/(sqrtx+1)`

Answer 2

Sửa đề: \(\dfrac{x-2\sqrt{x}+1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)

Ta có: \(\dfrac{x-2\sqrt{x}+1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)

\(=\dfrac{\left(\sqrt{x}-1\right)^2}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)

\(=\dfrac{\sqrt{x}-1}{\sqrt{x}+1}\)