\(=\dfrac{\sqrt{20+6\sqrt{11}}}{4}=\dfrac{\sqrt{\left(\sqrt{11}+3\right)^2}}{4}=\dfrac{\sqrt{11}+3}{4}\)
Đúng 2
Bình luận (0)
Các câu hỏi tương tự
Rút gọn
\(\dfrac{1}{\sqrt{11-2\sqrt{30}}}-\dfrac{3}{7-2\sqrt{10}}\)
thực hiện phép tính ( rút gọn biểu thức )
a) \(\left(\dfrac{3+2\sqrt{3}}{\sqrt{3}+2}-\dfrac{2+\sqrt{2}}{\sqrt{2}+1}\right)\left(\sqrt{3}+\sqrt{2}\right)\)
b) \(\left(2+\dfrac{11-\sqrt{11}}{1-\sqrt{11}}\right)\left(2+\dfrac{\sqrt{11}+11}{\sqrt{11}+1}\right)\)
\(\dfrac{\sqrt{3}+\sqrt{11+6\sqrt{2}}-\sqrt{5+2\sqrt{6}}}{\sqrt{2}+\sqrt{6+2\sqrt{5}}-\sqrt{7+2\sqrt{10}}}\)
rút gọn:giải hộ mình nha
bài 1 thực hiện pt
a)\(\sqrt{75}-2\sqrt{27}+\sqrt{48}\)
b)\(\dfrac{\left(12\sqrt{50}-8\sqrt{200}+\dfrac{7}{3}\sqrt{450}\right)}{\sqrt{10}}\)
c)\(\sqrt{8+2\sqrt{7}}-\sqrt{11-4\sqrt{7}}\)giải hộ mik
11) \(\dfrac{5+\sqrt{5}}{5-\sqrt{5}}\) + \(\dfrac{5-\sqrt{5}}{5+\sqrt{5}}\)
12) \(\dfrac{3+2\sqrt{3}}{\sqrt{3}}\) + \(\dfrac{2+\sqrt{2}}{\sqrt{2}+1}\) - \(\dfrac{1}{2-\sqrt{3}}\)
dfrac{sqrt{3-sqrt{5}}left(3+sqrt{5}right)}{sqrt{10}+sqrt{2}}dfrac{10+2sqrt{10}}{sqrt{5}+sqrt{2}}+dfrac{8}{1-sqrt{5}}dfrac{5+sqrt{7}}{9-sqrt{23+8sqrt{7}}}+dfrac{5-sqrt{7}}{2+sqrt{16+6sqrt{7}}}dfrac{1}{sqrt{2}+sqrt{2+sqrt{3}}}+dfrac{1}{sqrt{2}-sqrt{2+sqrt{3}}}
Đọc tiếp
\(\dfrac{\sqrt{3-\sqrt{5}}\left(3+\sqrt{5}\right)}{\sqrt{10}+\sqrt{2}}\)
\(\dfrac{10+2\sqrt{10}}{\sqrt{5}+\sqrt{2}}\)+\(\dfrac{8}{1-\sqrt{5}}\)
\(\dfrac{5+\sqrt{7}}{9-\sqrt{23+8\sqrt{7}}}\)+\(\dfrac{5-\sqrt{7}}{2+\sqrt{16+6\sqrt{7}}}\)
\(\dfrac{1}{\sqrt{2}+\sqrt{2+\sqrt{3}}}\)+\(\dfrac{1}{\sqrt{2}-\sqrt{2+\sqrt{3}}}\)
a. \(\dfrac{1}{3}.\sqrt{18}-\sqrt{192}-\dfrac{\sqrt{33}}{\sqrt{11}}+3\sqrt{5\dfrac{1}{3}}\)
b. \(\sqrt{\left(2\sqrt{3}-5\right)^2}-2\sqrt{7+4\sqrt{3}}\)
Thực hiện phép tính ( rút gọn biểu thức ) a) dfrac{sqrt{2}}{2sqrt{2}-3}+dfrac{1}{3+2sqrt{2}} b) dfrac{1}{sqrt{10}+sqrt{6}}+dfrac{1}{sqrt{6}-sqrt{10}}c) dfrac{-2}{3sqrt{8}}+dfrac{1}{3-2sqrt{2}}
Đọc tiếp
Thực hiện phép tính ( rút gọn biểu thức )
a) \(\dfrac{\sqrt{2}}{2\sqrt{2}-3}\)+\(\dfrac{1}{3+2\sqrt{2}}\) b) \(\dfrac{1}{\sqrt{10}+\sqrt{6}}\)+\(\dfrac{1}{\sqrt{6}-\sqrt{10}}\)
c) \(\dfrac{-2}{3\sqrt{8}}\)+\(\dfrac{1}{3-2\sqrt{2}}\)
26 tháng 7 2021 lúc 16:48
Thu gọn
\(\dfrac{15\sqrt{x}-11}{x+2\sqrt{x}-3}+\dfrac{3\sqrt{x}-2}{1-\sqrt{x}}-\dfrac{2\sqrt{x}+3}{3+\sqrt{x}}\)
\(\left(\dfrac{1}{\sqrt{x}}-\sqrt{x}\right):\left(\dfrac{1-\sqrt[]{x}}{x+\sqrt{x}}\right)\)
\(\dfrac{x\sqrt{x}+26\sqrt{x}-19}{x+2\sqrt{x}-3}-\dfrac{2\sqrt{x}}{\sqrt{x}-1}+\dfrac{\sqrt{x}-3}{\sqrt{x}-3}\)
\(\dfrac{15\sqrt{x}-11}{x+2\sqrt{x}-3}+\dfrac{3\sqrt{x}-2}{1-\sqrt{x}}-\dfrac{2\sqrt{x}+3}{\sqrt{x}+3}\)
RÚT GON