Question

\(\dfrac{a\sqrt{a}-8}{\sqrt{a}-2}\)+\(\dfrac{2a}{\sqrt{a}}\)

Answer 1

\(=a+2\sqrt{a}+4+2\sqrt{a}=a+4\sqrt{a}+4=\left(\sqrt{a}+2\right)^2\)​

Answer 2

\(=\dfrac{\left(\sqrt{a}-2\right)\left(a+2\sqrt{a}+4\right)}{\sqrt{a}-2}+2\sqrt{a}=a+2\sqrt{a}+4+2\sqrt{a}=\left(\sqrt{a}+2\right)^2\)

Answer 3

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