\(x=6-\dfrac{7}{3}=\dfrac{18-7}{3}=\dfrac{11}{3}\)
\(\dfrac{7}{3}+x=6\\ x=6-\dfrac{7}{3}\\ x=\dfrac{11}{3}\)
\(\dfrac{7}{3}+x=6\\ x=6-\dfrac{7}{3}\\ x=\dfrac{18}{3}-\dfrac{7}{3}\\ x=\dfrac{11}{3}\)
\(x=6-\dfrac{7}{3}=\dfrac{18-7}{3}=\dfrac{11}{3}\)
\(\dfrac{7}{3}+x=6\\ x=6-\dfrac{7}{3}\\ x=\dfrac{11}{3}\)
\(\dfrac{7}{3}+x=6\\ x=6-\dfrac{7}{3}\\ x=\dfrac{18}{3}-\dfrac{7}{3}\\ x=\dfrac{11}{3}\)
\(\dfrac{3}{7}\) + 4 = ?
\(\dfrac{5}{9}\) x 3 = ?
\(\dfrac{7}{8}\) - \(\dfrac{2}{9}\)= ?
5 - \(\dfrac{3}{4}\)= ?
\(\dfrac{5}{7}\) : 6 = ?
\(\dfrac{5}{6}\) x \(\dfrac{2}{7}\)= ?
3 + \(\dfrac{3}{4}\)= ?
\(\dfrac{3}{5}x\dfrac{4}{8}\) = ?
5 : \(\dfrac{3}{8}\)= ?
Mong mn trả lời
a,\(\dfrac{4}{9}\) : \(\dfrac{3}{10}\)
b,\(\dfrac{3}{7}\) x \(\dfrac{5}{7}\)
c,\(\dfrac{4}{9}\) : \(\dfrac{3}{2}\)
D \(\dfrac{3}{9}\) + \(\dfrac{5}{6}\) x \(\dfrac{2}{3}\)
E \(\dfrac{2}{7}\) x \(\dfrac{4}{3}\) + \(\dfrac{2}{6}\)
G \(\dfrac{4}{7}\) : 2 + \(\dfrac{4}{7}\)
Tính bằng cách thuận tiện nhất:
a) 60 x (\(\dfrac{7}{12}\) + \(\dfrac{4}{15}\))
b) \(\dfrac{1}{2}\) x \(\dfrac{2}{3}\) x \(\dfrac{3}{4}\) x \(\dfrac{4}{5}\) x \(\dfrac{5}{6}\) x \(\dfrac{6}{7}\) x \(\dfrac{7}{8}\) x \(\dfrac{8}{9}\)
405 : 27 x 516
\(\dfrac{6}{7}\) + \(\dfrac{2}{3}\) x \(\dfrac{5}{4}\)
\(\dfrac{9}{5}\) - \(\dfrac{6}{7}\) : \(\dfrac{11}{7}\)
A,\(\dfrac{3}{5}+\dfrac{1}{6}\)
B,\(4+\dfrac{2}{5}\)
C,\(\dfrac{25}{12}-\dfrac{7}{6}\)
D,\(\dfrac{9}{7}-\dfrac{7}{6}\)
E,\(\dfrac{3}{7}\) x \(\dfrac{2}{5}\)
a,\(\dfrac{2}{9}+\dfrac{1}{6}\)
b,\(\dfrac{5}{6}-\dfrac{4}{7}\)
c,\(\dfrac{3}{8}\)x\(\dfrac{6}{15}\)
d,\(\dfrac{7}{12}:\dfrac{4}{7}\)
e,\(\dfrac{4}{7}:3\)
a,\(\dfrac{2}{3}\)x\(\dfrac{5}{2}\):\(\dfrac{9}{5}\)
b,\(\dfrac{1}{3}\)x\(\dfrac{1}{4}\)+\(\dfrac{5}{6}\)
c,\(\dfrac{1}{2}\)-\(\dfrac{7}{8}\):\(\dfrac{7}{4}\)
d,\(\dfrac{6}{5}\)-\(\dfrac{4}{5}\)x\(\dfrac{3}{2}\)
\(\dfrac{6}{7}\) + \(\dfrac{2}{3}\) x \(\dfrac{5}{4}\)
\(\dfrac{9}{5}\) - \(\dfrac{6}{7}\): \(\dfrac{11}{7}\)
bài 1 :
a) \(\dfrac{2}{5}+\dfrac{3}{8}=\) b)\(\dfrac{7}{6}-\dfrac{2}{3}=\) c)\(\dfrac{5}{9}\times6\) d)\(\dfrac{8}{5}:\dfrac{4}{7}=\)
bài 2:
a) \(\dfrac{4}{5}+\) x =\(\dfrac{5}{6}\) b)x : \(\dfrac{7}{10}=5\)
bài 3 : hai xe ô tô chở được tất cả 16 tấn 8 tạ hàng . Xe ô tô thứ nhất chở được nhiều hơn xe ô tô thứ hai 2 tấn 6 tạ hàng . Hỏi mỗi xe chở được bao nhiêu tạ hàng
bài 4 :
145 \(\times\) 69 + 22 x 145 +145 x 8 + 145 =
a.\(\dfrac{x}{y}\) x \(\dfrac{3}{4}\) = \(\dfrac{5}{6}\) + \(\dfrac{1}{3}\)
b.\(\dfrac{7}{9}:\dfrac{x}{y}=\dfrac{10}{7}-\dfrac{13}{14}\)