Question

\(\dfrac{3}{x-1}\)=\(\dfrac{y+2}{8}\)=\(\dfrac{3}{4}\) tìm x,y

Answer 1

\(ĐK:x\ne1\\ PT\Leftrightarrow\left\{{}\begin{matrix}x-1=\dfrac{3\cdot4}{3}=4\\y+2=\dfrac{3\cdot8}{4}=6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=5\left(tm\right)\\y=4\end{matrix}\right.\)

Answer 2

\(\Leftrightarrow\left\{{}\begin{matrix}x=5\\y=4\end{matrix}\right.\)