Question

\(\dfrac{3\sqrt{2}-6}{\sqrt{2}-1}\)

Answer 1

\(\dfrac{3\sqrt{2}-6}{\sqrt{2}-1}=\dfrac{\left(3\sqrt{2}-6\right)\left(\sqrt{2}+1\right)}{\left(\sqrt{2}-1\right)\left(\sqrt{2}+1\right)}=\dfrac{6-3\sqrt{2}-6}{1}=-3\sqrt{2}\)

Answer 2

\(\dfrac{3\sqrt{2}-6}{\sqrt{2}-1}=-3\sqrt{2}\)