x.x=2.8
x2=16
x2=42 hoặc x = -4
vậy x=4 hoặc -4
\(\Leftrightarrow x^2=16\)
hay \(x\in\left\{4;-4\right\}\)
2/4=4/8
Vì 8:2 = 4
2/4=2.2 =>4/8
4.2
\(\dfrac{2}{x}=\dfrac{x}{8}\Rightarrow2.8=x.x=16\\ \Rightarrow x^2=16\\ \Rightarrow\left(\pm4\right)^2=16\\ \Rightarrow x=\pm4\)
ta có 2.8 = x.x
=> 16= x.x
=> x= 4; -4
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