Question

\(\dfrac{2+3\sqrt{2}}{\sqrt{2}}+\dfrac{3-\sqrt{3}}{\sqrt{3}-1}-\left(3+\sqrt{2}\right)\)

Answer 1

\(=\dfrac{\sqrt{2}\left(\sqrt{2}+3\right)}{\sqrt{2}}+\dfrac{\sqrt{3}\left(\sqrt{3}-1\right)}{\sqrt{3}-1}-3-\sqrt{2}\\ =\sqrt{2}+3+\sqrt{3}-3-\sqrt{2}\\ =\sqrt{3}\)

Answer 2

\(=3+\sqrt{2}+\sqrt{3}-3-\sqrt{2}=\sqrt{3}\)