Question

\(\dfrac{1}{\sqrt{6}-2}+\dfrac{1}{\sqrt{6}+2}\)

Answer 1

\(\dfrac{\sqrt{6}+2}{6-4}+\dfrac{\sqrt{6}-2}{6-4}=\dfrac{2\sqrt{6}}{6-4}=\sqrt{6}\)

Answer 2

⇔ \(\dfrac{\left(\sqrt{6}+2\right)+\left(\sqrt{6}-2\right)}{\left(\sqrt{6}-2\right)\left(\sqrt{6}+2\right)}\)

⇔ \(\dfrac{\sqrt{6}+2+\sqrt{6}-2}{2}=\dfrac{2\sqrt{6}}{2}=\sqrt{6}\)

Answer 3

=1(√6 + 2) + 1(√6 -2)/6-4

=√6 + 2 + √6 - 2/2

=2√6/2

=√6

/:là phân số nhé :')