Question

\(\dfrac{12}{11}\)-\(\dfrac{-7}{19}\)+\(\dfrac{12}{19}\)        \(\dfrac{5}{17}\)-\(\dfrac{25}{31}\)+\(\dfrac{12}{17}\)+\(\dfrac{-6}{31}\)
 

Answer 1

a: =12/11+7/19+12/19

=12/11+1

=23/11

b: =5/17+12/17-25/31-6/31

=1-1=0

 

Answer 2

\(\dfrac{12}{11}--\dfrac{7}{19}+\dfrac{12}{19}\)
\(=\dfrac{12}{11}+\left(\dfrac{7}{19}+\dfrac{12}{19}\right)\)
\(=\dfrac{12}{11}+1\)
\(=\dfrac{12+11}{11}=\dfrac{23}{11}\)
\(---------\)
\(\dfrac{5}{17}-\dfrac{25}{31}+\dfrac{12}{17}+-\dfrac{6}{31}\)
\(=\left(\dfrac{5}{17}+\dfrac{12}{17}\right)-\left(\dfrac{25}{31}+\dfrac{6}{31}\right)\)
\(=1-1=0\)

Answer 3

\(a,\dfrac{12}{11}-\dfrac{-7}{19}+\dfrac{12}{19}\\ =\dfrac{12}{11}+\dfrac{7}{19}+\dfrac{12}{19}\\= \dfrac{12}{11}+1\\ =\dfrac{23}{11}\\ b,\dfrac{5}{17}-\dfrac{25}{31}+\dfrac{12}{17}+\dfrac{-6}{31}\\ =\left(\dfrac{5}{17}+\dfrac{12}{17}\right)+\left(\dfrac{-25}{31}+\dfrac{-6}{31}\right)\\ =1+\left(-1\right)\\ =0\)