áp dụng BĐT buniacopxki,ta có:\(\left(x\sqrt{1-y^2}+y\sqrt{1-x^2}\right)^2\le\left(x^2+y^2\right)\left(1-y^2+1-x^2\right)=\left(x^2+y^2\right)\left(2-\left(x^2+y^2\right)\right)\)
↔\(1\le\left(x^2+y^2\right)\left(2-\left(x^2+y^2\right)\right)\)
Đặt x2+y2=a(a>=0),ta có:\(1\le a\left(2-a\right)\)↔a2-2a+1\(\ge\)0 hay\(\left(a-1\right)^2\ge0\)
dấu = xảy ra khi a=1 do đó x2+y2=1