Do \((d)\) đi qua \(A(2,1)\) và \(B(-1,3)\) nên:
\(\Rightarrow\left\{{}\begin{matrix}2m.2-\left(n-1\right).1=m\\2m.\left(-1\right)-\left(n-1\right).3=m\end{matrix}\right.\)
\(\Leftrightarrow \) \(\left\{{}\begin{matrix}3m-n=-1\\-3m-3n=-3\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}m=0\\n=1\end{matrix}\right.\)
Vậy \((m,n)=(0,1)\)