Ta có: \(\dfrac{a}{b}=\dfrac{b}{c}=\dfrac{c}{a}=\dfrac{a+b+c}{b+c+a}=1\)
\(\Rightarrow a=b=c\)
\(P=\dfrac{4a+6b+2017c}{4a-6b+2017c}=\dfrac{4a+6a+2017a}{4a-6a+2017a}=\dfrac{2027a}{2015a}=\dfrac{2027}{2015}\)
Tham khảo:
https://olm.vn/hoi-dap/detail/248147135218.html