a) `=(\sqrt3)/(\sqrt(2a)) = (\sqrt(6a))/(2a)`
b) `=(\sqrt(3ab))/(\sqrt2) = (\sqrt(6ab))/4`
a) \(\sqrt{\dfrac{3}{2a}}=\dfrac{\sqrt{3}}{\sqrt{2a}}=\dfrac{\sqrt{3}.\sqrt{2a}}{\sqrt{2a}.\sqrt{2a}}=\dfrac{\sqrt{6a}}{2a}\)
b) \(\sqrt{\dfrac{3ab}{2}}=\dfrac{\sqrt{3ab}}{\sqrt{2}}=\dfrac{\sqrt{3ab}.\sqrt{2}}{\sqrt{2}.\sqrt{2}}=\dfrac{\sqrt{6ab}}{2}\)
Sao mn đợi e làm xog r ms gửi bài giải hộ thế ạ
mãi mà mình ko có GP chán quá
a) \(\sqrt{\dfrac{3}{2a}}=\sqrt{\dfrac{6a}{4a^2}}=\dfrac{\sqrt{6a}}{2a}\)
b) \(\sqrt{\dfrac{3ab}{2}}=\sqrt{\dfrac{6ab}{4}}=\dfrac{\sqrt{6ab}}{2}\)