Question

a)tính P=(\(\frac{2\sqrt{x}}{\sqrt{x}+3}\)+\(\frac{\sqrt{x}}{\sqrt{x}-3}\)-\(\frac{3x+3}{x-9}\)):(\(\frac{2\sqrt{x}-2}{\sqrt{x}-3}\)-1)

b) tìm giá trị của x để P<\(\frac{1}{3}\)

c) tìm giá trị của x để P có GTLN

Answer 1

a) \(P=\left[\frac{2\sqrt{x}\left(\sqrt{x}-3\right)+\sqrt{x}\left(\sqrt{x}+3\right)-\left(3x+3\right)}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}\right]:\left[\frac{\left(2\sqrt{x}-2\right)-\left(\sqrt{x}-3\right)}{\sqrt{x}-3}\right]\left(ĐK:x\ge0;x\ne9\right)\) 

\(=\frac{2x-6\sqrt{x}+x+3\sqrt{x}-3x-3}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}:\frac{2\sqrt{x}-2-\sqrt{x}+3}{\sqrt{x}-3}\)

\(=\frac{-3\sqrt{x}-3}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}\cdot\frac{\sqrt{x}-3}{\sqrt{x}+1}\)

\(=\frac{-3\left(\sqrt{x}+1\right)}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}\cdot\frac{\sqrt{x}-3}{\sqrt{x}+1}\)

\(=\frac{-3}{\sqrt{x}+3}\)

 

 

 

 

Answer 2