Question

a)\(\left\{{}\begin{matrix}3x+y=3\\2x-y=7\end{matrix}\right.\)

b)\(\left\{{}\begin{matrix}2x+5y=8\\2x-3y=0\end{matrix}\right.\)

c)\(\left\{{}\begin{matrix}4x+3y=6\\2x+y=4\end{matrix}\right.\)

Answer 1

a: \(\Leftrightarrow\left\{{}\begin{matrix}5x=10\\2x-y=7\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=2x-7=-3\end{matrix}\right.\)

b: \(\Leftrightarrow\left\{{}\begin{matrix}8y=8\\2x=3y\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=1\\x=\dfrac{3}{2}\end{matrix}\right.\)

c: \(\Leftrightarrow\left\{{}\begin{matrix}4x+3y=6\\4x+2y=8\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=-2\\x=3\end{matrix}\right.\)

Answer 2

\(a,\left\{{}\begin{matrix}5x=10\\3x+y=3\end{matrix}\right.=>\left\{{}\begin{matrix}x=2\\3.2+y=3\end{matrix}\right.=>\left\{{}\begin{matrix}x=2\\y=-3\end{matrix}\right.\)

\(b,\left\{{}\begin{matrix}8y=8\\2x-3y=0\end{matrix}\right.=>\left\{{}\begin{matrix}y=1\\2x-3.1=0\end{matrix}\right.=>\left\{{}\begin{matrix}y=1\\x=\dfrac{3}{2}\end{matrix}\right.\)

\(c,\left\{{}\begin{matrix}4x+3y=6\\4x+2y=8\end{matrix}\right.=>\left\{{}\begin{matrix}y=-2\\2x-2=4\end{matrix}\right.=>\left\{{}\begin{matrix}y=-2\\x=3\end{matrix}\right.\)

Answer 3

a) \(\left\{{}\begin{matrix}3x+y=3\\2x-y=7\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}5x=10\\3x+y=3\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2\\y=-3\end{matrix}\right.\)

b) \(\left\{{}\begin{matrix}2x+5y=8\\2x-3y=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}8y=8\\2x-3y=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=1\\x=\dfrac{3}{2}\end{matrix}\right.\)

c) \(\left\{{}\begin{matrix}4x+3y=6\\2x+y=4\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}4x+3y=6\\4x+2y=8\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=-2\\2x+y=4\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=3\\y=-2\end{matrix}\right.\)