a, x( x - 6) = 0 <=> x = 0 ; x = 6
b, x ( x - 5) = 0 <=> x = 0 ; x = 5
c, ( x + 3)( x - 7) = 0 <=> x = -3 ; x = 7
a) \(x.\left(x-6\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=0\\x-6=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=6\end{matrix}\right.\)
b) làm tương tự
c) \(\left(x+3\right).\left(x-7\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x+3=0\\x-7=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-3\\x=7\end{matrix}\right.\)
a) Ta có: x(x-6)=0
nên \(\left[{}\begin{matrix}x=0\\x-6=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=6\end{matrix}\right.\)
b) Ta có: x(x-5)=0
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=5\end{matrix}\right.\)
c) Ta có: (x+3)(x-7)=0
\(\Leftrightarrow\left[{}\begin{matrix}x+3=0\\x-7=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=7\end{matrix}\right.\)