Question

\(\)a) \(\dfrac{3}{5}+\dfrac{11}{20}\)    b) \(\dfrac{5}{8}-\dfrac{4}{9}\)   c) \(\dfrac{9}{16}\) x \(\dfrac{4}{3}\)

d) \(\dfrac{4}{7}:\dfrac{8}{11}\)    e) \(\dfrac{3}{5}+\dfrac{4}{5}:\dfrac{2}{5}\)

Answer 1

a) _{^{\(\dfrac{3}{5}+\dfrac{11}{20}=\dfrac{12}{20}+\dfrac{11}{20}=\dfrac{23}{20}\)}}

b) _{^{\(\dfrac{5}{8}-\dfrac{4}{9}=\dfrac{45}{72}-\dfrac{32}{72}=\dfrac{13}{72}\)}}

c) _{^{\(\dfrac{9}{16}\times\dfrac{4}{3}=\dfrac{3}{4}\)}}

d) _{^{\(\dfrac{4}{7}:\dfrac{8}{11}=\dfrac{4}{7}\times\dfrac{11}{8}=\dfrac{11}{14}\)}}

e) _{^{\(\dfrac{3}{5}+\dfrac{4}{5}:\dfrac{2}{5}=\dfrac{3}{5}+\dfrac{4}{5}\times\dfrac{5}{2}=\dfrac{3}{5}+2=\dfrac{3}{5}+\dfrac{10}{5}=\dfrac{13}{5}\)}}

Answer 2

a, 23/20

b, 13/72

c, 3/4

d,11/14

e, 13/5

Answer 3

a)\(=\dfrac{12}{20}+\dfrac{11}{20}=\dfrac{23}{20}\)

b)\(=\dfrac{45}{72}-\dfrac{32}{72}=\dfrac{13}{72}\)

c)\(=\dfrac{9\times4}{16\times3}=\dfrac{3}{4}\)

d)\(=\dfrac{4}{7}\times\dfrac{11}{8}=\dfrac{11}{14}\)

e)\(=\dfrac{3}{5}+\dfrac{4}{2}=\dfrac{3}{5}+\dfrac{10}{5}=\dfrac{13}{5}\)

Answer 4

a) 12/20 + 11/20 = 23/20

b) 45/72 - 28/72 = 13/72

c) 3/4

d) 4/7 x 11/8 = 44/56 = 11/14

e) 3/5 + 4/5x 5/2 = 3/5 +2 = 13/5

Answer 5

a) \(\dfrac{3}{5}+\dfrac{11}{20}=\dfrac{12}{20}+\dfrac{11}{20}=\dfrac{23}{20}\)

b) \(\dfrac{5}{8}-\dfrac{4}{9}=\dfrac{45}{72}-\dfrac{32}{72}=\dfrac{13}{72}\)

c) \(\dfrac{9}{16}\times\dfrac{4}{3}=\dfrac{36}{48}=\dfrac{3}{4}\)

d) \(\dfrac{4}{7}:\dfrac{8}{11}=\dfrac{4}{7}\times\dfrac{11}{8}=\dfrac{44}{56}=\dfrac{11}{14}\)

e) \(\dfrac{3}{5}+\dfrac{4}{5}:\dfrac{2}{5}=\dfrac{3}{5}+2=\dfrac{3}{5}+\dfrac{2}{1}=\dfrac{3}{5}+\dfrac{10}{5}=\dfrac{13}{5}\)

Answer 6

a) _{^{58−49=4572−3272=137258−49=4572−3272=1372}}

c) _{^{47:811=47×118=111447:811=47×118=1114}}

e)