`(4x-1)^3=27`
`=>(4x-1)^3=3^3`
`=>4x-1=3`
`=>4x=4=>x=1`
Vậy `x=1`
\(\left(4x-1\right)^3=27\)
⇔ \(\left(4x-1\right)^3=3^3\)
⇒ \(4x-1=3\)
⇔ \(x=1\)
(4x-1)^3=3^3
4x-1=3 hoặc 4x-1=-3
x=1 hoặc x=-1/2
\(\left(4x-1\right)^3=27\)
\(\left(4x-1\right)^3=3^3\)
\(\left(4x-1\right)=3\)
\(4x=3+1=4\)
\(x=4:4=1\)
Ta có: \(\left(4x-1\right)^3=27\)
\(\Leftrightarrow4x-1=3\)
hay x=1