Question

(3x-2)^2-(5+2x)^2=0

 

Answer 1

các bn gúp mk đi

 

Answer 2

\(\Rightarrow\left(3x-2-5-2x\right)\left(3x-2+5+2x\right)=0\\ \Rightarrow\left[{}\begin{matrix}x-7=0\\5x+3=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=7\\x=-\dfrac{3}{5}\end{matrix}\right.\)

Answer 3

\(\left(2x-5\right)^2-\left(5+2x\right)^2=0\)

\(\Rightarrow\left(2x-5\right)^2+\left(2x-5\right)^2=0\)

Do \(\left(2x-5\right)^2\ge0\)

\(\Rightarrow\left(2x-5\right)^2=0\)

\(\Rightarrow2x-5=0\)

\(\Rightarrow x=\dfrac{5}{2}\)

Answer 4

\(\left(3x-2\right)^2-\left(5+2x\right)^2=0\)

\(\Leftrightarrow\left(3x-2-5-2x\right)\left(3x-2+5+2x\right)=0\)

\(\Leftrightarrow\left(x-7\right)\left(5x+3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=7\\5x=-3\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=7\\x=-\dfrac{3}{5}\end{matrix}\right.\)

Answer 5

\(\left(3x-2\right)^2-\left(2x+5\right)^2=0\)

\(\Leftrightarrow\left(3x-2-2x-5\right)\left(3x-2+2x+5\right)=0\)

\(\Leftrightarrow\left(x-7\right)\left(5x+3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=7\\x=-\dfrac{3}{5}\end{matrix}\right.\)