\(10-\left|x+1\right|=5\)
\(\Rightarrow\left|x+1\right|=5\)
\(\Rightarrow\left[{}\begin{matrix}x+1=5\\x+1=-5\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=4\\x=-6\end{matrix}\right.\)
`10 - |x+1|=5`
`|x+1|=10-5`
`|x+1|=5`
`@TH1 :
`x+1=-5`
`x=-5-1`
`x=-6`
`@TH2:`
`x+1=5`
`x=5-1`
`x=4`
Vậy `x= {-6;4}`
`10 - |x+1| = 5`
`|x-1| = 5`
`=>` \(\left[{}\begin{matrix}x-1=5\\x-1=-5\end{matrix}\right.\)
`<=>` \(\left[{}\begin{matrix}x=6\\x=-4\end{matrix}\right.\)
\(10-\left|x+1\right|=5\)
\(\left|x+1\right|=10-5\)
\(\left|x+1\right|=5\)
\(\Rightarrow x+1=\pm5\Rightarrow\left[{}\begin{matrix}x+1=5\\x+1=-5\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=4\\x=-6\end{matrix}\right.\)
\(10 − | x + 1 | = 5\)
\(| x + 1 |=10-5\)
\(\Leftrightarrow\left[{}\begin{matrix}x+1=5\\x+1=-5\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=5-1\\x=-5-1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-6\end{matrix}\right.\)
10 - |x + 1| = 5
x + 1 = 10 - 5
x + 1 = 5
chia thành 2 trường hợp :
trường hợp 1 :
x + 1 = 5
x = 5 - 1
x = 4
trường hợp 2 :
x + 1 = -5
x = (-5) - 1
x = - 6
vậy x ∈ { 5 ; -6 }