1)
\(\overrightarrow{CA}=\left(1-m;m\right)\\ \overrightarrow{CB}=\left(-3-m;m+5\right)\)
Tam giác ABC vuông tại C\(\Rightarrow\overrightarrow{CA}.\overrightarrow{CB}=\overrightarrow{0}\Leftrightarrow\left(m-1\right)\left(m+3\right)+m\left(m+5\right)=0\)
Tìm m rồi thay vào C
2) \(\overrightarrow{AB}=\left(4;-3\right),\overrightarrow{AC}=\left(12;-9\right)\Rightarrow\overrightarrow{AC}=3\overrightarrow{AB}\Rightarrow\)A,B,C thẳng hàng
b)\(E\left(x;0\right)\)
\(\overrightarrow{AE}=\left(x+3;-4\right)\)
A, B, E thẳng hàng \(\Leftrightarrow4.\left(-4\right)=-3\left(x+3\right)\Leftrightarrow x=\dfrac{7}{3}\)
Vậy \(E\left(\dfrac{7}{3};0\right)\)