Question

Answer 1

\(\dfrac{2x^4y-6x^2y^7}{2x^2}\)

\(=\dfrac{2x^4y}{2x^2}-\dfrac{6x^2y^7}{2x^2}\)

\(=x^2y-3y^7\)

=>a=1; b=-3

\(a\cdot b=1\cdot\left(-3\right)=-3\)

Answer 2

\(\left(2x^4y-6x^2y^7\right):\left(2x^2\right)=x^2y-3y^7\Rightarrow\left\{{}\begin{matrix}a=1\\b=-3\end{matrix}\right.\)

\(\Rightarrow a.b=1.\left(-3\right)=-3\)