`(1 - x)(1+ x + x^2) + x(x^2 - 5) = 11`
`<=> 1^3 - x^3 + x^3 - 5x = 11`
`<=> 1 - 5x = 11`
`<=> 5x = -10`
`<=> x = -2`
Vậy `x = -2`
\(\left(1-x\right)\left(1+x+x^2\right)+x\left(x^2-5\right)=11\)
\(1-x^3+x^3-5x=11\)
\(1-5x=11\)
\(5x=1-11\)
\(5x=-10\)
\(x=-2\)