\(a.x+\left|\dfrac{-2}{5}\right|=\left|\dfrac{-5}{3}\right|\\ =>x+\dfrac{2}{5}=\dfrac{5}{3}\\ =>x=\dfrac{5}{3}-\dfrac{2}{5}=\dfrac{19}{6}\\ b.\left|-1+\dfrac{1}{3}\right|-x=\dfrac{3}{2}\\ =>\dfrac{2}{3}-x=\dfrac{3}{2}\\ =>x=\dfrac{2}{3}-\dfrac{3}{2}\\ =>x=\dfrac{-5}{6}\\ c.x-\left|\dfrac{-4}{5}\right|=-2\dfrac{1}{4}\\ =>x-\dfrac{4}{5}=-\dfrac{9}{2}\\ =>x=-\dfrac{9}{2}+\dfrac{4}{5}=-\dfrac{37}{10}\\ d.-\left|1\dfrac{1}{5}\right|+x=3\dfrac{1}{2}\\ =>-\dfrac{6}{5}+x=\dfrac{7}{2}\\ =>x=\dfrac{7}{2}+\dfrac{6}{5}=\dfrac{47}{10}\)
e: \(x-\left|1\dfrac{1}{6}\right|=\dfrac{5}{21}\)
=>\(x-\dfrac{7}{6}=\dfrac{5}{21}\)
=>\(x=\dfrac{5}{21}+\dfrac{7}{6}=\dfrac{10}{42}+\dfrac{49}{42}=\dfrac{59}{42}\)
f: \(x-\left|-\dfrac{2}{3}\right|=-\left|-\dfrac{9}{4}\right|\)
=>\(x-\dfrac{2}{3}=-\dfrac{9}{4}\)
=>\(x=-\dfrac{9}{4}+\dfrac{2}{3}=-\dfrac{27}{12}+\dfrac{8}{12}=-\dfrac{19}{12}\)
g: \(x+\left|-1\dfrac{2}{3}\right|=\left|-\dfrac{3}{4}\right|\)
=>\(x+\dfrac{5}{3}=\dfrac{3}{4}\)
=>\(x=\dfrac{3}{4}-\dfrac{5}{3}=\dfrac{9}{12}-\dfrac{20}{12}=-\dfrac{11}{12}\)
h: \(x-\left|-\dfrac{3}{5}\right|=\left|-\dfrac{2}{3}\right|\)
=>\(x-\dfrac{3}{5}=\dfrac{2}{3}\)
=>\(x=\dfrac{2}{3}+\dfrac{3}{5}=\dfrac{10}{15}+\dfrac{9}{15}=\dfrac{19}{15}\)