\(1\dfrac{1}{4}x^2y\left(\dfrac{-6}{5}xy\right)\left(-2\dfrac{1}{3}xy\right)\\ =\dfrac{5}{4}x^2y\left(\dfrac{-6}{5}xy\right)\left(-\dfrac{7}{3}xy\right)\\ =\left(\dfrac{5}{4}\cdot\dfrac{-6}{5}\cdot\dfrac{-7}{3}\right)\cdot\left(x^2\cdot x\cdot x\right)\cdot\left(y\cdot y\cdot y\right)\\ =\dfrac{7}{2}x^4y^3\)
\(1\dfrac{1}{4}x^2y\left(-\dfrac{6}{5}xy\right)\left(-2\dfrac{1}{3}xy\right)\)
\(=\left[\dfrac{5}{4}.\left(-\dfrac{6}{5}\right).\left(-\dfrac{7}{3}\right)\right]\left(x^2.x.x\right).\left(y.y.y\right)\)
\(=\dfrac{7}{2}x^4y^3\)