Question

Answer 1

\(\dfrac{1}{3}x+\dfrac{2}{5}\left(x-1\right)=0\\ \Leftrightarrow\dfrac{1}{3}x+\dfrac{2}{5}x-\dfrac{2}{5}=0\\ \Leftrightarrow\left(\dfrac{1}{3}+\dfrac{2}{5}\right)x=\dfrac{2}{5}\\ \Leftrightarrow\dfrac{11}{15}\cdot x=\dfrac{2}{5}\\ \Leftrightarrow x=\dfrac{2}{5}:\dfrac{11}{15}\\ \Leftrightarrow x=\dfrac{6}{11}\)

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Answer 2

\(\dfrac{1}{3}x+\dfrac{2}{5}\left(x-1\right)=0\)
\(\Rightarrow\dfrac{1}{3}x+\dfrac{2}{5}x-\dfrac{2}{5}=0\)
\(\Rightarrow\dfrac{11}{15}x=\dfrac{2}{5}\)
\(\Rightarrow x=\dfrac{6}{11}\)