\(\dfrac{3-4x}{7}=\dfrac{-2}{9}\)
\(\Leftrightarrow\left(3-4x\right)\cdot9=\left(-2\right)\cdot7\)
\(\Leftrightarrow27-36x=-14\)
\(\Leftrightarrow36x=27-\left(-14\right)=41\)
\(\Leftrightarrow x=41:36=\dfrac{41}{36}\)
Vậy \(x=\dfrac{41}{36}\)
\(\#PeaGea\)
\(\dfrac{3-4x}{7}=\dfrac{-2}{9}\)
=>\(\dfrac{4x-3}{7}=\dfrac{2}{9}\)
=>\(4x-3=2\cdot\dfrac{7}{9}=\dfrac{14}{9}\)
=>\(4x=\dfrac{14}{9}+3=\dfrac{14}{9}+\dfrac{27}{9}=\dfrac{41}{9}\)
=>\(x=\dfrac{41}{9}:4=\dfrac{41}{36}\)
Câu 1
a) (3 - 4x)/7 = -2/9
9(3 - 4x) = -2.7
27 - 36x = -14
36x = 27 + 14
36x = 41
x = 41/36