Question

Answer 1

a.

ĐKXĐ: \(x\ne2\)

\(\dfrac{6}{x-2}-\dfrac{2x}{x-2}+\dfrac{3x+1}{x-2}\)

\(=\dfrac{6-2x+3x+1}{x-2}=\dfrac{x+7}{x-2}\)

b.

ĐKXĐ: \(x\ne-4\)

\(\dfrac{2x-1}{x+4}+\dfrac{3x-2}{x+4}-\dfrac{4x-3}{x+4}\)

\(=\dfrac{2x+1+3x-2-\left(4x-3\right)}{x+4}\)

\(=\dfrac{x+2}{x+4}\)

Answer 2

a/\(\dfrac{6}{x-2}-\dfrac{2x}{x-2}+\dfrac{3x+1}{x-2}\)(ĐKXĐ: \(x\ne2\))
\(=\dfrac{6-2x+3x+1}{x-2}=\dfrac{x+7}{x-2}\)
b/\(\dfrac{2x-1}{x+4}+\dfrac{3x-2}{x+4}-\dfrac{4x-3}{x+4}\)(ĐKXĐ: \(x\ne-4\))
\(=\dfrac{2x-1+3x-2-4x+3}{x+4}\)
\(=\dfrac{x+2}{x+4}\)
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