Question

Answer 1

\(\left(2x-3\right)^2-\left(2x-3\right)\left(2x+3\right)=0\)

\(\Rightarrow\left(2x-3\right)\left[\left(2x-3\right)-\left(2x+3\right)\right]=0\)

\(\Rightarrow\left(2x-3\right)\left(2x-3-2x-3\right)=0\)

\(\Rightarrow\left(2x-3\right)\cdot\left(-6\right)=0\)

\(\Rightarrow2x-3=0\)

\(\Rightarrow2x=3\)

\(\Rightarrow x=\dfrac{3}{2}\)