Question

Answer 1

`#3107.101107`

8.

`1/9x^2 - 1/64y^2`

`= (1/3x)^2 - (1/8y)^2`

`= (1/3x - 1/8y)(1/3x + 1/8y)`

`=> (x/3 - y/8)(x/3 + y/8)`

`=> D.`

Answer 2

\(\frac19x^2-\frac{1}{64}y^2\\=\left(\frac13x\right)^2-\left(\frac18y\right)^2\\=\left(\frac13x-\frac18y\right)\left(\frac13x+\frac18y\right)\\=\left(\frac x3-\frac y8\right)\left(\frac x3+\frac y8\right)\\\rightarrow D\)