\(c)x^2+4x+4-25y^2\\=(x^2+2\cdot x\cdot2+2^2)-25y^2\\=(x+2)^2-(5y)^2\\=(x+2-5y)(x+2+5y)\\---\\n)8x^3-27y^3\\=(2x)^3-(3y)^3\\=(2x-3y)[(2x)^2+2x\cdot3y+(3y)^2]\\=(2x-3y)(4x^2+6xy+9y^2)\)
#\(Toru\)
`x^2 +4x+4-25y^2`
`=(x^2+4x+4) - (5y)^2`
`= (x+2)^2 -(5y)^2`
`= (x+2-5y)(x+2+5y)`
`8x^3 -27y^3`
`= (2x)^3 - (3y)^3`
`=(2x-3y)(4x^2 + 6xy+9y^2)`