Question

Answer 1

`x^2+2xy+y^2-9`

`=(x^2+2xy+y^2) -3^2`

`=(x+y)^2 -3^2`

`=(x+y-3)(x+y+3)`

`x^3-125`

`=x^3-5^3`

`=(x-5)(x^2 +5x+25)`

Answer 2

\(b)x^2+2xy+y^2-9\\=(x^2+2xy+y^2)-9\\=(x+y)^2-3^2\\=(x+y-3)(x+y+3)\\---\\m)x^3-125\\=x^3-5^3\\=(x-5)[x^2+x\cdot5+5^2]\\=(x-5)(x^2+5x+25)\)
#\(Toru\)