Bài 10 này là 1 dạng chung anh làm mẫu 2 câu xong em áp dụng theo ha.
\(a,\left(2x-3\right)^2-\left(x-1\right)^2=0\\ \Leftrightarrow\left[\left(2x-3\right)-\left(x-1\right)\right].\left[\left(2x-3\right)+\left(x-1\right)\right]=0\\ \Leftrightarrow\left(x-2\right).\left(3x-4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x-2=0\\3x-4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{4}{3}\end{matrix}\right.\)
\(2,\\ \left(2x+1\right)^2-\left(x-1\right)^2=0\\ \Leftrightarrow\left[\left(2x+1\right)-\left(x-1\right)\right].\left[\left(2x+1\right)+\left(x-1\right)\right]=0\\ \Leftrightarrow\left(x+2\right).3x=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x+2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\)
