Câu hỏi của bonk

Question

TV Cuber · Accepted Answer

a) `-2x +3 >= 0``<=> -2x >= -3``<=> x <= 3/2``b) -5x >=0``<=> x<=0``c)-3x+7 >=0``<=> -3x >=-7``<=> x<=7/3``d)3x+7 >=0``<=> 3x>=-7``<=> x >=-7/3``e) x/3 >=0``=> x >=0``f) -5x >=0``=> x <=0``f) 4-x >=0``=> x <=4``h) 1+x^2 >=0`mà `1+x^2 > 0 AA x``=> x in NN^#`i) `(-5)/(x^2 +6) >=0`Do -5 <0`=> x^2 +6 <0 (vô-lí)``=> biểu thức ko có nghĩaCâu trả lời: a) `-2x +3 >= 0``<=> -2x >= -3``<=> x <= 3/2``b) -5x >=0``<=> x<=0``c)-3x+7 >=0``<=> -3x >=-7``<=> x<=7/3``d)3x+7 >=0``<=> 3x>=-7``<=> x >=-7/3``e) x/3 >=0``=> x >=0``f) -5x >=0``=> x <=0``f) 4-x >=0``=> x <=4``h) 1+x^2 >=0`mà `1+x^2 > 0 AA x``=> x in NN^#`i) `(-5)/(x^2 +6) >=0`Do -5 <0`=> x^2 +6 <0 (vô-lí)``=> biểu thức ko có nghĩa

TV Cuber · Answer

`j) 2/x^2 >=0``=> x^2 >0``=> x ne 0``k)1/(-1+x)>=0``=> -1+x >0``=> x>1``l) 4/(x+3) >=0``=> x+3 >0``=> x>-3``m) 4x^2 >=0``=> x^2 >=0 ``=> x in NN``n) -3x^2 >=0``=> x^2 <=0``=> x^2 =0``=> x=0``0) x^2 -2x +1 >=0``=> (x-1)^2 >=0 ( luôn -đúng)``=> x in NN`P)`-x^2 -2x -1 >=0``<=> -(x^2 +2x+1)>=0``<=> -(x+1)^2 >=0``=> (x+1)^2 <=0`Mà `(x+1)^2 >=0 AAx``=> x+1 =0``=> x=-1`Câu trả lời: `j) 2/x^2 >=0``=> x^2 >0``=> x ne 0``k)1/(-1+x)>=0``=> -1+x >0``=> x>1``l) 4/(x+3) >=0``=> x+3 >0``=> x>-3``m) 4x^2 >=0``=> x^2 >=0 ``=> x in NN``n) -3x^2 >=0``=> x^2 <=0``=> x^2 =0``=> x=0``0) x^2 -2x +1 >=0``=> (x-1)^2 >=0 ( luôn -đúng)``=> x in NN`P)`-x^2 -2x -1 >=0``<=> -(x^2 +2x+1)>=0``<=> -(x+1)^2 >=0``=> (x+1)^2 <=0`Mà `(x+1)^2 >=0 AAx``=> x+1 =0``=> x=-1`

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