Question

Answer 1

`(5x^2 -2x +10)^2 = (3x^2 +10x -8)^2`

`<=> (5x^2 -2x +10)^2 - (3x^2 +10x -8)^2=0`

`<=> (5x^2 -2x +10 +3x^2 +10x -8)(5x^2-2x+10-3x^2 -10x +8)=0`

`<=> (8x^2 +8x +2)(2x^2 -12x +18)=0`

`<=> (4x^2 + 4x +1)(x^2 - 6x +9) =0`

`<=> (2x+1)^2(x-3)^2 =0`

`<=> [(x = -1/2),(x=3):}`

 

Answer 2

=>(5x^2-2x+10-3x^2-10x+8)(5x^2-2x+10+3x^2+10x-8)=0

=>(2x^2-12x+18)(8x^2+8x+2)=0

=>(x-3)^2*(2x+1)^2=0

=>x=3 hoặc x=-1/2